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python實(shí)現(xiàn)兩個經(jīng)緯度點(diǎn)之間的距離和方位角的方法

 更新時間:2019年07月05日 14:51:51   作者:bboyzqh  
今天小編就為大家分享一篇python實(shí)現(xiàn)兩個經(jīng)緯度點(diǎn)之間的距離和方位角的方法,具有很好的參考價值,希望對大家有所幫助。一起跟隨小編過來看看吧

最近做有關(guān)GPS軌跡上有關(guān)的東西,花費(fèi)心思較多,對兩個常用的函數(shù)總結(jié)一下,求距離和求方位角,比較精確,歡迎交流!

1. 求兩個經(jīng)緯點(diǎn)的方位角,P0(latA, lonA), P1(latB, lonB)(很多博客寫的不是很好,這里總結(jié)一下)

def getDegree(latA, lonA, latB, lonB):
  """
  Args:
    point p1(latA, lonA)
    point p2(latB, lonB)
  Returns:
    bearing between the two GPS points,
    default: the basis of heading direction is north
  """
  radLatA = radians(latA)
  radLonA = radians(lonA)
  radLatB = radians(latB)
  radLonB = radians(lonB)
  dLon = radLonB - radLonA
  y = sin(dLon) * cos(radLatB)
  x = cos(radLatA) * sin(radLatB) - sin(radLatA) * cos(radLatB) * cos(dLon)
  brng = degrees(atan2(y, x))
  brng = (brng + 360) % 360
  return brng

2. 求兩個經(jīng)緯點(diǎn)的距離函數(shù):P0(latA, lonA), P1(latB, lonB)

def getDistance(latA, lonA, latB, lonB):
  ra = 6378140 # radius of equator: meter
  rb = 6356755 # radius of polar: meter
  flatten = (ra - rb) / ra # Partial rate of the earth
  # change angle to radians
  radLatA = radians(latA)
  radLonA = radians(lonA)
  radLatB = radians(latB)
  radLonB = radians(lonB)
 
  pA = atan(rb / ra * tan(radLatA))
  pB = atan(rb / ra * tan(radLatB))
  x = acos(sin(pA) * sin(pB) + cos(pA) * cos(pB) * cos(radLonA - radLonB))
  c1 = (sin(x) - x) * (sin(pA) + sin(pB))**2 / cos(x / 2)**2
  c2 = (sin(x) + x) * (sin(pA) - sin(pB))**2 / sin(x / 2)**2
  dr = flatten / 8 * (c1 - c2)
  distance = ra * (x + dr)
  return distance

以上這篇python實(shí)現(xiàn)兩個經(jīng)緯度點(diǎn)之間的距離和方位角的方法就是小編分享給大家的全部內(nèi)容了,希望能給大家一個參考,也希望大家多多支持腳本之家。

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