sql中的left join及on、where條件關鍵字的區(qū)別詳解
更新時間：2018年08月31日 08:27:25 作者：abce
LEFT JOIN 關鍵字從左表（table1）返回所有的行，即使右表（table2）中沒有匹配。如果右表中沒有匹配，則結果為 NULL。這篇文章主要介紹了sql中的left join以及on、where關鍵字的區(qū)別,需要的朋友可以參考下
LEFT JOIN 關鍵字會從左表 (table_name1) 那里返回所有的行，即使在右表 (table_name2) 中沒有匹配的行。
LEFT JOIN 關鍵字語法
SELECT column_name(s) FROM table_name1 LEFT JOIN table_name2 ON table_name1.column_name=table_name2.column_name
注釋：在某些數據庫中， LEFT JOIN 稱為 LEFT OUTER JOIN。
創(chuàng)建兩張表并插入一些數據
create table class( class_id int, class_name varchar(20), class_grade char(1) ); insert into class values (1,'語文','A'); insert into class values (2,'數學','B'); insert into class values (3,'英語','C'); create table score( class_id int, stu_id varchar(20), Score int ); insert into score values (1,'A001',91); insert into score values (2,'A001',95); insert into score values (1,'A002',82); insert into score values (2,'A002',87); insert into score values (3,'B003',65);
查看表中的數據
mysql> select * from class; +----------+------------+-------------+ | class_id | class_name | class_grade | +----------+------------+-------------+ | 1 | 語文 | A | | 2 | 數學 | B | | 3 | 英語 | C | +----------+------------+-------------+ 3 rows in set (0.00 sec) mysql> select * from score; +----------+--------+-------+ | class_id | stu_id | Score | +----------+--------+-------+ | 1 | A001 | 91 | | 2 | A001 | 95 | | 1 | A002 | 82 | | 2 | A002 | 87 | | 3 | B003 | 65 | +----------+--------+-------+ 5 rows in set (0.00 sec) mysql>
比較下面幾組查詢結果
--如果你對left join足夠熟悉的話，先不要看結果，是否可以直接說出下面查詢的結果
mysql> select * from class A left join score B on A.class_id=B.class_id; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | 1 | A001 | 91 | | 2 | 數學 | B | 2 | A001 | 95 | | 1 | 語文 | A | 1 | A002 | 82 | | 2 | 數學 | B | 2 | A002 | 87 | | 3 | 英語 | C | 3 | B003 | 65 | +----------+------------+-------------+----------+--------+-------+ 5 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and 1=1; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | 1 | A001 | 91 | | 2 | 數學 | B | 2 | A001 | 95 | | 1 | 語文 | A | 1 | A002 | 82 | | 2 | 數學 | B | 2 | A002 | 87 | | 3 | 英語 | C | 3 | B003 | 65 | +----------+------------+-------------+----------+--------+-------+ 5 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and 1=0; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql> select * from class A left join score B on 1=0; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec)
mysql> left join的最重要特點是：不管on后面是什么條件，都會返回左表中的所有行！
mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='語文'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | 1 | A001 | 91 | | 1 | 語文 | A | 1 | A002 | 82 | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 4 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='數學'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 2 | 數學 | B | 2 | A001 | 95 | | 2 | 數學 | B | 2 | A002 | 87 | | 1 | 語文 | A | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 4 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='英語'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 3 | 英語 | C | 3 | B003 | 65 | | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='體育'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql>
如果on后面的條件是左表中的列(and leftTable.colName='***'),左表中滿足條件的行和右表中的行進行匹配(根據on leftTable.id=rightTable.id)；左表中不滿足條件的行，直接輸出，其對應的右表中的列都是null。
mysql> select * from class A left join score B on A.class_id=B.class_id and B.Score=90; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and B.Score=65; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 3 | 英語 | C | 3 | B003 | 65 | | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql>
如果on后面的條件是右表中的列(and rightTable.colName='***'),首先會根據(and rightTable.colName='***')過濾掉右表中不滿足條件的行；然后，左表中的行根據(on leftTable.id=rightTable.id)和右表中滿足條件的行進行匹配。
mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='語文' and B.Score=90; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='語文' and B.Score=91; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | 1 | A001 | 91 | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='體育' and B.Score=90; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='體育' and B.Score=82; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | NULL | NULL | NULL | | 2 | 數學 | B | NULL | NULL | NULL | | 3 | 英語 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql>
/**********************過濾條件在on中時**********************/
總結一下，如果 left join on leftTable.id=rightTable.id 后還有其他條件：
(1)and leftTable.colName='***'，過濾左表，但是左表不滿足條件的行直接輸出，并將右表對應部分置為null
(2)and rightTable.colName='***'，過濾右表，對左表沒有影響
(3)and leftTable.colName='***' and rightTable.colName='***'，就是上面(1)和(2)一起發(fā)揮作用
不管on后面有哪些條件，left join都要返回左表中的所有行！
mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='語文'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | 1 | A001 | 91 | | 1 | 語文 | A | 1 | A002 | 82 | +----------+------------+-------------+----------+--------+-------+ 2 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='數學'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 2 | 數學 | B | 2 | A001 | 95 | | 2 | 數學 | B | 2 | A002 | 87 | +----------+------------+-------------+----------+--------+-------+ 2 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='英語'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 3 | 英語 | C | 3 | B003 | 65 | +----------+------------+-------------+----------+--------+-------+ 1 row in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='體育'; Empty set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where B.Score=90; Empty set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where B.Score=91; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | 1 | A001 | 91 | +----------+------------+-------------+----------+--------+-------+ 1 row in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='語文' and B.Score=90; Empty set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='語文' and B.Score=91; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 語文 | A | 1 | A001 | 91 | +----------+------------+-------------+----------+--------+-------+ 1 row in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='體育' and B.Score=90; Empty set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='體育' and B.Score=91; Empty set (0.00 sec) mysql>
/**********************過濾條件在where中時**********************/
過濾條件寫在where中時，先根據where條件對表進行過濾，然后再執(zhí)行l(wèi)eft join
總結
以上所述是小編給大家介紹的sql中的left join及on、where關鍵字的區(qū)別詳解，希望對大家有所幫助，如果大家有任何疑問請給我留言，小編會及時回復大家的。在此也非常感謝大家對腳本之家網站的支持！
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